Posted Fri Aug 26, 2005 5:12 pm GMT by hjg24
Lets say after the turn you have 20 outs that will win the hand for you on the river. That is a percentage of 42.55. Now lets say the pot is $2,000 before your call and to call it will cost $740. Can someone tell me how to relate the pot size and call with the percentage of your odds and whether your should call it.
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Posted Fri Aug 26, 2005 5:20 pm GMT by zinn0
I may be wrong because I am just really starting to calculate odds, etc, so please go gentle on me if I am incorrect. With 20 outs, you would have 42.55% chance of improving your hand, or 2.35-1. The pot is now $2,000, and the bet is $740. You will need to put up $740 to win $2,000. Roughly 2.7-1 for your money. For every dollar you put up, you will get 2.7 back, assuming you make your hand and win. Your pot odds ditctate that you should probably make this call since you are getting a high return on your money, greater than 2.35-1, which is the chance you have to win the hand.
Posted Fri Aug 26, 2005 5:28 pm GMT by hjg24
I am looking at my odds chart. It is 1.35-1 and not 2.35-1
Posted Fri Aug 26, 2005 5:30 pm GMT by zinn0
Duly noted---sorry about that.
Posted Fri Aug 26, 2005 5:38 pm GMT by supafrey
Think about it in simple terms at first. You need to bet X amount of money to win nearly ~3x back. You are 2/5 to win. It's a good call. If you're certain that you will be able to get even more bets on the river, should you hit, then it's definitely a good call, because even implied odds are figured in. Cappish?
Posted Fri Aug 26, 2005 5:39 pm GMT by hjg24
IMO, I think going by percentages will be easier then odds. With the 20 outs it gives you the percentage of 42.5. If your betting 740 to win 2000, then wont the percentage be (740/2000) 37%. Since 42.5 is obviously greater then 37 you should call. Is this how you correctly figure it out using percentages?
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