Posted Thu Mar 04, 2004 11:12 pm GMT by robertbbb
would appreciate anyone explaining how to change percentages numbers to odds.
robertbbb
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Posted Thu Mar 04, 2004 11:26 pm GMT by alphakenny1
well think about it. if you have a 33% chance of winning so that means 33/99 time you will win. so then if you reduce the fraction that comes out to be 1/3. so 1 out of 3 time you win. so that means two of three times you lose. so you're chance of winning are 2(losses) to 1(win).
another example you have a chance to win 90% of the time so that means you are 9(wins) to 1(losses) to win.
Posted Fri Mar 05, 2004 11:02 am GMT by K-rug
With all due respect, you are kidding right?
Posted Fri Mar 05, 2004 11:53 am GMT by karasz
sklansky/malmuth's texas holdem book has this exact thing...
Posted Fri Mar 05, 2004 5:44 pm GMT by JohnnyCache
A quick rule is each out you have is worth about 2% on the flop and a little more then two percent after the flop . . . if only need one card, but have two cards to draw it, add the outs twice. IE 8 outs, 16%, two cards to draw them, 32%.
This method not exact but is good for calculations for uncommon outs . . .
Posted Thu Apr 29, 2004 6:01 pm GMT by MLT_Slim
Odds to percent = if odds are 4:1 to convert to probability(%) = 1/(4 + 1) = 1/5 = .20 = 20%
Probability to Odds = if probablity is 35% to convert to odds =
(100 - 35):35 or 65:35 divide both sides by 35 and you get 1.86:1 or approx 2:1
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