% of the time you won't flop a pair? |
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Posted Mon Mar 27, 2006 2:55 pm GMT by kainARGH
I heard somewhere 2/3rds of the time , without a pocket pair , you won't flop a pair on the board. How relatively true is this ?
The comment sparked my curiosity.
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Posted Mon Mar 27, 2006 5:33 pm GMT by xDiamond_CutteRx
It is true you will only flop a pair with two unpaired cards about 36% of the time.
The calculation for this is: P(a) = 1 - 44/50 + 1 - 43/49 + 1 - 42/48
Posted Mon Mar 27, 2006 6:29 pm GMT by Sid Lambert
You may like our Pre-Flop Calculator.
keep in mind tho that, that number means flopping *only* one pair, so it takes out the chances of trips, two pair, full house, that kinda thing
Posted Mon Mar 27, 2006 7:00 pm GMT by kainARGH
| Sid Lambert wrote: | You may like our Pre-Flop Calculator.
keep in mind tho that, that number means flopping *only* one pair, so it takes out the chances of trips, two pair, full house, that kinda thing |
Yea , i like that tool 
But it says;
Chance of getting 1 Pair on the flop: 26.94%
Which is different then what i'm told , unless im looking at that wrong.
*edit* thanks xDiamond_CutteRx , exactly what i was looking for.
Posted Mon Mar 27, 2006 7:16 pm GMT by Sid Lambert
Yeah, that is the chance of getting one pair, but also not having two pair, or 3 of a kind, or something better...so its showing the chance of a pair minus chances of two pair, minus chance of 3 of a kind, minus full house, blah blah.../b
Posted Mon Mar 27, 2006 7:17 pm GMT by kainARGH
| Sid Lambert wrote: | | Yeah, that is the chance of getting one pair, but also not having two pair, or 3 of a kind, or something better...so its showing the chance of a pair minus chances of two pair, minus chance of 3 of a kind, minus full house, blah blah.../b |
thank you thank you 
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