Posted Mon Jul 31, 2006 10:09 pm GMT by GoldFire
Alright, this has to do with 2 side pots, and the best way I can think to describe it is to just setup a sample scenario.
Player A has 5000 chips, Player B has 200, and Player C has 100. If Player A bets 1000, and B and C both call, how do you determine the side pots? I can do it if Player B has 100 and C has 200, but I don't get how it works the other way around.
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Posted Mon Jul 31, 2006 10:29 pm GMT by khaosanroad
| GoldFire wrote: | Alright, this has to do with 2 side pots, and the best way I can think to describe it is to just setup a sample scenario.
Player A has 5000 chips, Player B has 200, and Player C has 100. If Player A bets 1000, and B and C both call, how do you determine the side pots? I can do it if Player B has 100 and C has 200, but I don't get how it works the other way around. |
Main pot= 300 anybody can win this
1st side pot= 200 best hand between A and B
2d side pot= 4800 player A is getting this back regardless.
Posted Mon Jul 31, 2006 10:30 pm GMT by cayouche
Any player can only win what he puts in, so...
Main pot is 300 chips (3 times what C had) that any player is competing for.
Side pot #1 is 200 chips (2 times the remaining 100 B had) that player A and B can win.
Side pot #2 is the remaining 800 (A's bet) that only A can win, therefore he keeps it.
I hope it's clear.
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