
Quick probability question |
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Posted Mon Dec 11, 2006 11:03 am GMT by KingOHearts
How far off center of the bell curve is it to see 121 hands without seeing a PP once?
And I quit too, so who knows how long it would have continued.
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Posted Fri Jan 05, 2007 8:28 pm GMT by jbark
the probability of no PPs in 121 consecutive hands is .0006 or .06%
cheers
jerry
Posted Mon Jan 08, 2007 3:49 pm GMT by Adam Marshall
Why do I come up with something totally different?
Chance of not getting a pocket pair = 48/51
So it's just (48/51) to the 121st power? Or am I losing my mojo?
Posted Mon Jan 08, 2007 3:58 pm GMT by Dave B
Hey Adam, you get the same thing.
48/51=.94118
.94118^121=.0006522
Posted Mon Jan 08, 2007 4:03 pm GMT by Adam Marshall
Whoops. You're right.
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