What's the probability of this? |
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Posted Thu Mar 10, 2005 6:19 pm GMT by FirebirdGM
I'm just curious what the odds of both players in a heads-up game getting pocket aces is. Then, the probability of that happening the very next hand. I saw this in a Tiger Gaming tournament I was in Which gives me more reason to believe that it's rigged...
I'm not 100% sure, but this is what I tried:
4/52 * 3/51 * 2/50 * 1/49
Which equals something like .000369%.
Not sure if I'm right though.
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Posted Thu Mar 10, 2005 7:32 pm GMT by xDiamond_CutteRx
As long as there are only two players, yes, that should be correct.
Posted Mon Mar 14, 2005 7:50 pm GMT by Adam Marshall
This is one of my pet peeves.
You math is correct, but assumes that it happens on one particular hand. Many hands are actually dealt. I think a more fair way to analyze it would be "what are the chances that the other guy will have aces when I get aces?"
So it'd be 2/(50x49) or 1 in 1225 or .08% or so.
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